Answer
$\frac{3x^2 + 4x - 15}{(x + 2)^2(x + 3)}$
Work Step by Step
For $\frac{3x - 5}{x^2 + 4x + 4} = \frac{}{(x+2)^2(x + 3)}$,
$\frac{3x - 5}{x^2 + 4x + 4} = \frac{(3x - 5)[x + 3]}{(x + 2)^2[x + 3]}$,
The equivalent rational expression of $\frac{3x - 5}{x^2 + 4x + 4}$ with the given denominator is $\frac{(3x -5)[x + 3]}{(x + 2)^2[x + 3]}$ or $\frac{3x^2 + 4x - 15}{(x + 2)^2(x + 3)}$.
