Answer
(2x+1+z)(2x+1-z)
Work Step by Step
4$x^{2}$+4x+1-$z^{2}$=($(2x)^{2}$-2*x*1+$1^{2}$)-$z^{2}$=
$(2x+1)^{2}$-$z^{2}$=(2x+1+z)(2x+1-z)
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