## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 447: 15

#### Answer

$(4a-3)^{2}$

#### Work Step by Step

16$a^{2}$-24a+9=$(4a)^{2}$ -(2)(4a)(3)+$3^{2}$=$(4a-3)^{2}$

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