Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 447: 22



Work Step by Step

$y^{3}$+12$y^{2}$+36y=y($y^{2}$+12y+36)= y($y^{2}$+2*y*6)+$6^{2}$)=y$(y+6)^{2}$
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