Answer
$(2x-3y)(4x-y)$
Work Step by Step
$8x^2-14xy+3y^2$
Factors of 3: 1 and 3, -1 and -3
Factors of 8: 1 and 8, 2 and 4, -1 and -8, -2 and -4
$(2x-y)(4x-3y)$
$2x*4x+2x*(-3y)+4x*-y+(-y)(-3y)$
$8x^2-6xy-4xy+3y^2$
$8x^2-10xy+3y^2$
$(2x-3y)(4x-y)$
$2x*4x+2x*-y+4x*-3y+(-3y)(-y)$
$8x^2-2xy-12xy+3y^2$
$8x^2-14xy+3y^2$