Answer
$(x-3)(x-4)$
Work Step by Step
$-7x+12+x^2$
$x^2-7x+12$
Factors of 12: -1 and -12, -2 and -6, -3 and -4, 1 and 12, 2 and 6, 3 and 4
$x^2-7x+12$
$(x-3)(x-4)$
$x*x+x*-4+x*-3+(-3)(-4)$
$x^2-4x-3x+12$
$x^2-7x+12$
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