Answer
$(6x-7)(3x+2)$
Work Step by Step
$18x^2-9x-14$
Factors of -14: 1 and -14, 2 and -7, 7 and -2, 14 and -1
Factors of 18: 1 and 18, 2 and 9, 3 and 6, -1 and -18, -2 and -9, -3 and -6
$(6x+7)(3x-2)$
$6x*3x+6x*-2+7*3x+7*-2$
$18x^2-12x+21x-14$
$18x^2+9x-14$
$(6x-7)(3x+2)$
$6x*3x+6x*2+(-7)*3x+(-7)*2$
$18x^2+12x-21x-14$
$18x^2-9x-14$