Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Review: 74

Answer

$20,22$

Work Step by Step

let's call the first number $x$, and the second will be $x+2$ We know that $x(x+2) = 440$ $x^2 + 2x - 440= 0$ $x^2 + 22 x - 20x - 440= 0$ $x(x+22) - 20 (x + 22) = 0$ $(x-20)(x+22) = 0$ And because we know x should be a positive even integer. $x = 20, x \ne -22$ Therefore the numbers ae $20,22$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.