## Algebra: A Combined Approach (4th Edition)

$20,22$
let's call the first number $x$, and the second will be $x+2$ We know that $x(x+2) = 440$ $x^2 + 2x - 440= 0$ $x^2 + 22 x - 20x - 440= 0$ $x(x+22) - 20 (x + 22) = 0$ $(x-20)(x+22) = 0$ And because we know x should be a positive even integer. $x = 20, x \ne -22$ Therefore the numbers ae $20,22$