## Algebra: A Combined Approach (4th Edition)

let's call the first number $x$, and the second will be $x+1$ We know that $x(x+1) = 380$ $x^2 + x - 380 = 0$ $x^2 + 20 x - 19x - 380 = 0$ $x(x+20) - 19 (x + 20) = 0$ $(x-19)(x+20) = 0$ And because we know x should be a positive integer. $x = 19, x \ne -20$