Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Review - Page 475: 69

Answer

$x = 9$

Work Step by Step

The are of the square is $x^2$ let's compare it to 81. $x^2 = 81$ $x^2 - 81 = 81- 81 = 0 $ $(x-9)(x+9)=0$ $x = 9$ And $x\ne -9$ because it is a length, and a length cannot be negative number.
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