Answer
-3, 5
Work Step by Step
We know that $(x^{a})^{b}=x^{a\times b}$ (where $x$ is a real number and $a$ and $b$ are integers).
Therefore, one possible solution to the given exercise is $x^{-15}=(x^{-3})^{5}$, as $-3\times5=-15$.
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