Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set - Page 356: 125

Answer

-3, -7

Work Step by Step

We know that $x^{a}\times x^{b}=x^{a+b}$ (where $x$ is a real number and $a$ and $b$ are integers). Therefore, one possible solution to the given exercise is $z^{-10}=z^{-3}\times z^{-7}$.
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