Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set - Page 356: 124



Work Step by Step

We know that $a^{-n}=\frac{1}{a^{n}}$ (where $a$ is a real number and $n$ is a positive integer). Therefore, $\frac{1}{49}=\frac{1}{7\times7}=\frac{1}{7^{2}}=7^{-2}$.
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