Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set: 43

Answer

$-\frac{4a^{5}}{b}$

Work Step by Step

We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer). Therefore, $\frac{-24a^{6}b}{6ab^{2}}=\frac{-24}{6}\times a^{6-1}\times b^{1-2}=-4\times a^{5}\times b^{-1}=-4\times a^{5}\times\frac{1}{b}=-\frac{4a^{5}}{b}$.
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