Answer
$p^{4}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $\frac{p^{2}p}{p^{-1}}=\frac{p^{2+1}}{p^{-1}}=\frac{p^{3}}{p^{-1}}=p^{3}\times p=p^{3+1}=p^{4}$.