Answer
$y^{6}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $\frac{y^{3}y}{y^{-2}}=\frac{y^{3+1}}{y^{-2}}=\frac{y^{4}}{y^{-2}}=y^{4}\times y^{2}=y^{4+2}=y^{6}$.