Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations by Graphing - Exercise Set - Page 292: 60

Answer

Answers may vary. One system of equations is $x-y=5$ $x+y=1$

Work Step by Step

Please see the screenshot of the tables for the two equations. Purple line: $x-y=5$ Green line: $x+y=1$ If we substitute the $x$ and $y$ for $3$ and $-2$ respectively, for the purple line: $x-y=5$ $3-(-2)=5$ $5=5$ (true) Green line: $x+y=1$ $3+(-2)=1$ $1=1$ (true) Purple line: $x-y=5$ $x-y+y-5=5+y-5$ $x-5=y$ ($m=1$, y-intercept is -5) Green line: $x+y=1$ $x+y-x=1-x$ $y=-x+1$ ($m=-1$, y-intercept is 1)
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