## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 4 - Section 4.1 - Solving Systems of Linear Equations by Graphing - Exercise Set: 50

#### Answer

a. Lines intersecting at a single point b. One solution

#### Work Step by Step

$8y+6x=4$ $8y=-6x+4$ $y=-\frac{3}{4}x+\frac{1}{2}$ $4y-2=3x$ $4y=3x+2$ $y=\frac{3}{4}x+\frac{1}{2}$ a. The slope of the first line is $-\frac{3}{4}$ , whereas the slope of the second line is $\frac{3}{4}$. Since the two slopes are not equal, the two lines are neither parallel nor identical and must intersect at a single point. b. Because the two lines are neither parallel nor identical and must intersect at a point, this system has one solution and is consistent.

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