#### Answer

a. Lines intersecting at a single point
b. One solution

#### Work Step by Step

$8y+6x=4$
$8y=-6x+4$
$y=-\frac{3}{4}x+\frac{1}{2}$
$4y-2=3x$
$4y=3x+2$
$y=\frac{3}{4}x+\frac{1}{2}$
a.
The slope of the first line is $-\frac{3}{4}$ , whereas the slope of the second line is $\frac{3}{4}$. Since the two slopes are not equal, the two lines are neither parallel nor identical and must intersect at a single point.
b.
Because the two lines are neither parallel nor identical and must intersect at a point, this system has one solution and is consistent.