Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations by Graphing - Exercise Set - Page 292: 49


a. These are identical lines. b. Since they are identical lines, the system has infinitely many solutions (all points on the line are solutions).

Work Step by Step

We have $6y + 4x = 6$ and $3y - 3 = -2x$ Rearrange the second equation as $3y+2x=3$ Now multiply both sides of the second equation by two (2): We get $2(3y+2x)=2(3)$, which is $6y + 4x = 6$ (the same as the first equation). Hence, we have the same two equations which correspond to the same line.
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