Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations by Graphing - Exercise Set - Page 292: 49

Answer

a. These are identical lines. b. Since they are identical lines, the system has infinitely many solutions (all points on the line are solutions).

Work Step by Step

We have $6y + 4x = 6$ and $3y - 3 = -2x$ Rearrange the second equation as $3y+2x=3$ Now multiply both sides of the second equation by two (2): We get $2(3y+2x)=2(3)$, which is $6y + 4x = 6$ (the same as the first equation). Hence, we have the same two equations which correspond to the same line.
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