## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 2 - Section 2.3 - Further Solving Linear Equations - Exercise Set - Page 119: 54

x = -15

#### Work Step by Step

$\frac{x}{5} - 7 = \frac{x}{3} - 5$ Subtract $\frac{x}{3}$ from both sides: $\frac{x}{5} - \frac{x}{3} - 7 = -5$ $\frac{3x}{15} - \frac{5x}{15} - 7 = -5$ $\frac{-2x}{15} - 7 = -5$ Add 7 to both sides: $\frac{-2x}{15} = 2$ Multiply both sides by the reciprocal, $-\frac{15}{2}$: $-\frac{15}{2}(\frac{-2x}{15}) = 2(-\frac{15}{2}$) x = -15

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