## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 2 - Section 2.3 - Further Solving Linear Equations - Exercise Set: 53

x = 10

#### Work Step by Step

$\frac{x}{2} - 1 = \frac{x}{5} + 2$ Subtract $\frac{x}{5}$ from both sides: $\frac{x}{2} - \frac{x}{5} - 1 = 2$ $\frac{5x}{10} - \frac{2x}{10} - 1 = 2$ $\frac{3x}{10} - 1 = 2$ Add 1 to both sides: $\frac{3x}{10}$ = 3 Multiply both sides by the reciprocal of the coefficient, $\frac{10}{3}$: $\frac{10}{3}(\frac{3x}{10}$) = 3($\frac{10}{3}$) x = 10

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