Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.3 - Further Solving Linear Equations - Exercise Set: 41

Answer

y = $\frac{14}{3}$

Work Step by Step

5y + 2(y - 6) = 4(y + 1) - 2 Distribute: 5y + 2y - 12 = 4y + 4 - 2 Combine like terms: 7y - 12 = 4y + 2 Subtract 4y from both sides: 3y - 12 = 2 Add 12 to both sides: 3y = 14 Divide both sides by 3: y = $\frac{14}{3}$
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