Answer
$f(x)^{-1}=2x-1$
Work Step by Step
$f(x)=\frac{x+1}{2}$
$y=\frac{x+1}{2}$
Then we swap $x$ with $y$
$x=\frac{y+1}{2}$
$2x=y+1$
$y=2x-1$
$f(x)^{-1}=2x-1$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 13 - Cumulative Review - Page 970: 54
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