Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Cumulative Review: 49

Answer

{$\frac{2}{99}$}

Work Step by Step

Step 1: $\log (x+2)-\log x=2$ Step 2: $\log \frac{x+2}{x}=2$ Step 3: $\frac{x+2}{x}=10^{2}$ Step 4: $\frac{x+2}{x}=100$ Step 5: $x+2=100x$ Step 6: $100x-x=2$ Step 7: $99x=2$ Step 8: $x=\frac{2}{99}$ Step 9: Therefore, the solution set is {$\frac{2}{99}$}
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