Answer
$5$
Work Step by Step
Let $P=(x_{1},y_{1})=(-3,3)$ and $Q=(x_{2},y_{2})=(1,0)$
Finding the distance between P and Q,
$d(P,Q)=\sqrt {(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$
$d(P,Q)=\sqrt {(1-(-3))^{2}+(0-3)^{2}}$
$d(P,Q)=\sqrt {(1+3)^{2}+(-3)^{2}}$
$d(P,Q)=\sqrt {(4)^{2}+(-3)^{2}}$
$d(P,Q)=\sqrt {16+9}$
$d(P,Q)=\sqrt {25}=5$
