Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Cumulative Review - Page 968: 18

Answer

$\frac{5(a+2)}{3(a-5)(a+5)}$

Work Step by Step

We simplify as follows: $\frac{2}{3a-15}-\frac{a}{25-a^{2}}$ $=\frac{2}{3(a-5)}-\frac{a}{-(a-5)(a+5)}$ $=\frac{-2(a+5)}{-3(a-5)(a+5)}-\frac{3a}{-3(a-5)(a+5)}$ $=\frac{-5a-10}{-3(a-5)(a+5)}$ $=\frac{5(a+2)}{3(a-5)(a+5)}$
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