Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Cumulative Review - Page 968: 12

Answer

$2a^{3}(5a+1)(2a+5)$

Work Step by Step

Step 1: $20a^{5}+54a^{4}+10a^{3}$ Step 2: $2a^{3}(10a^{2}+27a+5)$ Step 3: $2a^{3}(10a^{2}+2a+25a+5)$ Step 4: $2a^{3}(2a(5a+1)+5(5a+1))$ Step 5: $2a^{3}(5a+1)(2a+5)$
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