Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Cumulative Review - Page 968: 15

Answer

$$t=5$$

Work Step by Step

To simplify the equation, you need to determine the least common multiple of $2$, $9$, and $18$. You may do this by prime factorization: $$2: 2$$ $$9: 3\:x\:3$$ $$18: 2 \:x\: 9 = 2\: x\: 3\: x\: 3$$ Then multiply each factor the greatest number of times it occurs in either number. $2$ - one occurrence $3$ - two occurrences Hence, the LCM would be $2\: x\: 3\: x\: 3$ = $18$ The next step is to multiple both sides by the $LCM =18$ $$\frac{t-4}{2}(18) - \frac{t-3}{9}(18) = \frac{5}{18}(18)$$ Simplifying this will give us: $$9(t-4)-2(t-3)=5$$ Expand: $$9t - 36 - 2t + 6 = 5$$ which is now equal to $$7t - 30 = 5$$ Simplifying further: $$7t = 35$$ Dividing both sides by 7: $$t=5$$
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