Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.3 - Exponential Functions - Exercise Set - Page 861: 30

Answer

$x=\dfrac{2}{5}$

Work Step by Step

$32^{x}=4$ Rewrite $32$ as $2^{5}$ and $4$ as $2^{2}$ $(2^{5})^{x}=2^{2}$ Transform the left side of the equation into a power that has the product of $5$ and $x$ as its exponent: $2^{5x}=2^{2}$ If $2^{5x}=2^{2}$, then $5x=2$: $5x=2$ Solve for $x$: $x=\dfrac{2}{5}$
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