Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.3 - Exponential Functions - Exercise Set - Page 861: 29



Work Step by Step

$9^{x}=27$ Rewrite $9$ as $3^{2}$ and $27$ as $3^{3}$: $(3^{2})^{x}=3^{3}$ On the left side of the equation, multiply both exponents: $3^{2x}=3^{3}$ If $3^{2x}=3^{3}$, then $2x=3$ $2x=3$ Solve for $x$: $x=\dfrac{3}{2}$
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