## Algebra: A Combined Approach (4th Edition)

$x=-\dfrac{3}{2}$
$\dfrac{1}{27}=3^{2x}$ Rewrite $27$ as $3^{3}$: $\dfrac{1}{3^{3}}=3^{2x}$ Take $3^{3}$ to the numerator by changing the sign of its exponent: $3^{-3}=3^{2x}$ If $3^{-3}=3^{2x}$, then $2x=-3$ $2x=-3$ Solve for $x$: $x=-\dfrac{3}{2}$