Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Cumulative Review: 31



Work Step by Step

$\sqrt[4] 32=\sqrt[4] (16\times2)=\sqrt[4]16\times\sqrt[4]2=2\sqrt[4]2$ We know that $\sqrt[4]16=2$, because $2^{4}=16$.
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