Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Cumulative Review - Page 913: 26

Answer

$y^{\frac{1}{3}}$

Work Step by Step

$\sqrt[15] y^{5}=y^{\frac{5}{15}}=y^{\frac{5\div5}{15\div5}}=y^{\frac{1}{3}}$
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