Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Cumulative Review: 24



Work Step by Step

$\sqrt[4] (162a^{4}b^{5})=\sqrt[4] (81a^{4}b^{4}\times 2b)=\sqrt[4] (81a^{4}b^{4})\times \sqrt[4]2b=3ab\sqrt[4]2b$ We know that $\sqrt[4] (81a^{4}b^{4})=3ab$, because $(3ab)^{4}=3^{4}a^{4}b^{4}=81a^{4}b^{4}$.
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