Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.6 - Further Graphing of Quadratic Functions - Exercise Set - Page 820: 21

Answer

Vertex: $(-4, -1/2)$ Opens upward x-intercepts: -5, -3 y-intercept: 0

Work Step by Step

$f(x)=1/2*x^2+4x+15/2$ $y=1/2(x^2+8x+15)$ $y+1/2 = 1/2(x^2+8x+15+1)$ $y+1/2 = 1/2 (x^2+8x+16)$ $y+1/2 = 1/2(x+4)^2$ $y+1/2-1/2 = 1/2(x+4)^2-1/2$ $y= 1/2(x+4)^2-1/2$ Vertex: $(-4, -1/2)$ Opens upward $x=0$ $f(x)=1/2*x^2+4x+15/2$ $f(0)=1/2*0^2+4*0+15/2$ $f(0)=1/2*0+0+15/2$ $f(0)=0+15/2$ $f(0)=15/2$ $y=0$ $y+1/2 = 1/2(x+4)^2$ $0+1/2 = 1/2(x+4)^2$ $1/2 = 1/2(x+4)^2$ $1/2*2 =2* 1/2(x+4)^2$ $1 = (x+4)^2$ $\sqrt 1 = \sqrt {(x+4)^2}$ $±1 = x+4$ $-1=x+4$ $-1-4=x+4-4$ $-5=x$ $1=x+4$ $1-4=x+4-4$ $-3=x$ x-intercepts: -5, -3 y-intercept: 0
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