Answer
Vertex: (1,0)
Opens downward
x-intercept: -1
y-intercept: -1
Work Step by Step
$f(x)=-x^2+2x-1$
$f(x)=-(x^2-2x+1)$
$f(x)=-(x-1)(x-1)$
$f(x)=-(x-1)^2$
Vertex: (1,0)
Opens downward
$x=0$
$f(x)=-x^2+2x-1$
$f(0)=-0^2+2*0-1$
$f(0)=-0+0-1$
$f(0)=-1$
$y=0$
$0=-(x-1)^2$
$\sqrt 0 =\sqrt {-(x-1)^2}$
$0 = ±(x+1)$
$0=-x-1$
$0+x=-x-1+x$
$x = -1$
$0=x+1$
$0-1=x+1-1$
$-1=x$
x-intercept: -1
y-intercept: -1
