Chapter 11 - Section 11.6 - Further Graphing of Quadratic Functions - Exercise Set - Page 820: 16

Vertex: $(2,0)$ Opens downward x-intercept: 2 y-intercept: -4

$f(x)=-x^2+4x-4$ $f(x)=-(x^2-4x+4)$ $f(x)=-(x-2)^2$ Vertex: $(2,0)$ Opens downward $x=0$ $f(x)=-(x-2)^2$ $f(0)=-(0-2)^2$ $f(0)=-(2^2)$ $f(0)=-4$ $y=0$ $f(x)=-(x-2)^2$ $0=-(x-2)^2$ $0*-1=-(x-2)^2$ $0=(x-2)^2$ $\sqrt 0 = \sqrt {(x-2)^2}$ $0=(x-2)$ $0+2=x-2+2$ $2=x$ x-intercept: 2 y-intercept: -4