Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 811: 51

Answer

Please see the graph. The red line is the original function, and the blue line is $y=f(x)+1$.

Work Step by Step

The graph of $f(x)$ has the points as follows: $(-5, -2)$, $(-4, -1)$, $(-3, 0)$, $(-2, 1)$, $(-1, .5)$, $(0,0)$, $(1,1)$, $(2,2)$, $(3,3)$, $(4,4)$, $(5,5)$ For the function $y=f(x)+1$, we increase the y-value of all points of $f(x)$ by one unit. This means our new function has the points $(-5, -1)$, $(-4, 0)$, $(-3, 1)$, $(-2, 2)$, $(-1, 1.5)$, $(0,1)$, $(1,2)$, $(2,3)$, $(3,4)$, $(4,5)$, $(5,6)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.