Answer
Please see the graph.
Work Step by Step
$F(x)=-x^2+2$
Axis of symmetry:
$F(x)=-x^2+2$
$F(x)=-(x− 0)^2+2$
$x=0$
Vertex:
$F(x)=-x^2+2$
$F(0)=-(0)^2+2$
$F(0)=0+2$
$F(0)=2$
The red line is the function $F(x)=-x^2+2$, the line at $x=0$ is the axis of symmetry, and the point $(0,2)$ is the vertex.
