Answer
Please see the graph.
Work Step by Step
$G(x)=3x^2+1$
Axis of symmetry:
$G(x)=3x^2+1$
$G(x)=3(x− 0)^2+1$
$x=0$
Vertex:
$G(x)=3x^2+1$
$G(0)=3(0)^2+1$
$G(0)=3*0+1$
$G(0)=0+1$
$G(0)=1$
The red line is the function $G(x)=3x^2+1$, the line at $x=0$ is the axis of symmetry, and the point $(0,1)$ is the vertex.
