Answer
Please see the graph.
Work Step by Step
$H(x)=(x-1)^2$
Axis of symmetry:
$H(x)=(x-1)^2$
$x=1$
Vertex:
$H(x)=(x-1)^2$
$H(1)=(1-1)^2$
$H(1)=0^2$
$H(1)=0$
The dot at $(1, 0)$ is the vertex, the black line at $x=1$ is the axis of symmetry, and the red line that goes through the dot is the function $h(x)=(x-1)^2$.
