Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 808: 4

Please see the graph.

$f(x)=(x+5)^2$ Axis of symmetry: $f(x)=(x+5)^2$ $f(x)=(x- -5)^2$ $x=-5$ is the axis of symmetry Vertex: $f(x)=(x+5)^2$ $x=-5$ $f(-5)=(x+5)^2$ $f(-5)=(-5+5)^2$ $f(-5)=0^2$ $f(-5)=0$ The vertex is the orange dot, the axis of symmetry is the black vertical line, and the green line is the function.