Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 808: 7

Please see the graph.

$h(x)=(x+2)^2$ Axis of symmetry: $h(x)=(x+2)^2$ $h(x)=(x- -2)^2$ $x=-2$ Vertex: $h(x)=(x+2)^2$ $h(-2)=(-2+2)^2$ $h(-2)=0^2$ $h(-2)=0$ The dot at $(-2, 0)$ is the vertex, the black line at $x=-2$ is the axis of symmetry, and the red line that goes through the dot is the function $h(x)=(x+2)^2$.