Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 790: 81

Answer

a) 11.615 m/s b) 11.612 m/s c) 25.975 mph

Work Step by Step

b) Distance = rate * time For Contador, we use the following variables rate (in meters/second) = $x$ time (in seconds) = $y$ Total distance = 119 kilometers (119,000 meters) Contador: $119000 =x*y$ Voeckler was .0034 meters/second faster and took 3 seconds fewer Voeckler: $119000 = (x+.0034)*(y-3)$ $119000 = (x+.0034)*(y-3)$ $119000 = x*y+x*-3+.0034*y+.0034*-3$ $119000 = xy-3x+.0034y-.0102$ $119000 =x*y$ $119000 = xy-3x+.0034y-.0102$ $xy=xy-3x+.0034y-.0102$ $xy-xy=xy-3x+.0034y-.0102-xy$ $0=-3x+.0034y-.0102$ $0+3x=-3x+.0034y-.0102+3x$ $3x=.0034y-.0102$ $3x/3=(.0034y-.0102)/3$ $x=.001133333y-.0034$ $119000 =x*y$ $119000 =(.001133333y-.0034)*y$ $119000 =.001133333y^2-.0034y$ $119000-119000 =.001133333y^2-.0034y-119000$ $0 =.001133333y^2-.0034y-119000$ $a=.0011333333$, $b=-.0034$, $c=-119000$ $y=(-b±\sqrt{b^2-4ac})/2a$ $y=(.0034±\sqrt{(-.0034)^2-4*.00113333*-119000})/2*.00113333$ $y=(.0034±\sqrt{(-.0034)^2+4*.113333*1190})/.00226666$ $y=(.0034±\sqrt{.00001156+539.46508})/.00226666$ $y=(.0034±\sqrt{539.46509156})/.00226666$ $y=(.0034±23.22638)/.00226666$ We want only the positive square root as we are looking for time. $y=(.0034+23.22638)/.00226666$ $y=23.22978/.00226666$ $y=10248.432$ $119000/10248.432 =11.6115$ m/s Rounded to three decimal places, $x=11.612$ m/s. a) Vocekler was .0034 m/s faster, so $11.6115+.0034=11.6149$ Rounded to three decimal places, Vocekler's speed was $11.615$ m/s c) $11.615$ meters/second $* 3.28084$ feet/meter $*3600$ seconds/hour = $137149.92$ feet/hour $137149.92$ feet/hour $*1/5280$ miles/feet = $25.975$ mi/hr
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