Answer
Answers may vary. One possible equation is $x^3-4x=0$
Work Step by Step
$0$, $2i$, and $-2i$ are solutions
$x=0$
$x=2i$
$x=-2i$
$(x)(x-2i)(x+2i)$
$((x*x+x*2i+x*(-2i)+(-2i)(2i)))*x$
$(x^2+2xi-2xi-4i^2)*x$
$(x^2-4i^2)*x$
$(x^2-4(\sqrt {-1}*\sqrt {-1}))*x$
$(x^2-4(\sqrt {-1*-1}))*x$
$(x^2-4(\sqrt 1))*x$
$(x^2-4(\sqrt 1))*x$
$(x^2-4*1)*x$
$(x^2-4)*x$
$x^3-4x$