Answer
Answers may vary. One possible equation is $x^3-39x+70=0$
Work Step by Step
$x=2$, $x=5$, and $x=-7$ are solutions
$(x-2)(x-5)(x+7)$
$(x*x+x*(-5)+(-2)*x+(-2)(-5))*(x+7)$
$(x^2-5x-2x+10)*(x+7)$
$(x^2-7x+10)*(x+7)$
$x^2*x+x^2*7+(-7x)*x+(-7x)*7+10*x+10*7$
$x^3+7x^2-7x^2-49x+10x+70$
$x^3-39x+70$