Answer
$x= \sqrt {11}, -\sqrt {11}, -1, 1$
Work Step by Step
$x^4-12x^2+11=0$
$(x^2-1)(x^2-11)=0$
$x^2-1=0$
$x^2=1$
$\sqrt {x^2} =\sqrt 1$
$x=±1$
$x^2-11=0$
$x^2=11$
$\sqrt {x^2} =\sqrt {11}$
$x=±\sqrt {11}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 787: 30
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