Answer
$a=-\sqrt3, -\sqrt 2, \sqrt 2, \sqrt 3$
Work Step by Step
$a^4-5a^2+6=0$
$(a^2-3)(a^2-2)=0$
$a^2-3=0$
$a^2=3$
$\sqrt{a^2}=\sqrt3$
$a=±\sqrt 3$
$a^2-2=0$
$a^2=2$
$\sqrt{a^2}=\sqrt2$
$a=±\sqrt 2$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 787: 29
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