Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 787: 22

Answer

$m=2, 5$

Work Step by Step

$(m-6)^2+5(m-6)+4=0$ $m-6=x$ $(m-6)^2+5(m-6)+4=0$ $x^2+5x+4=0$ $(x+4)(x+1)=0$ $x+4=0$ $x=-4$ $x+1=0$ $x=-1$ $m-6=x$ $x=-4$ $m-6=-4$ $m=2$ $x=-1$ $m-6=-1$ $m=5$
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