#### Answer

$(y^{2}+6)(\sqrt 2y-1)(\sqrt 2y+1)$

#### Work Step by Step

Step 1: Let u=$y^{2}$
$=2u^{2}+11u-6$
Step 2: Factor $2u^{2}+11u-6$
=(u+6)(2u-1)
Step 3: Substitute back $u=y^{2}$
$=(y^{2}+6)(2y^{2}-1)$
Step 4: Factor $2y^{2}-1$
$=(\sqrt 2y-1)(\sqrt 2y+1)$
Step 5: Place all of the factors into one
$(y^{2}+6)(\sqrt 2y-1)(\sqrt 2y+1)$